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求中位数。先sort()排序,对2取余数,判断余数是否是0。
注意的是在/运算中会自动保存成float,在调用比如data[len(data)/2]时候data里面的数必须是整形的,所以要int()转换一下。def checkio(data): x=len(data)%2 data.sort() if x==0: y=len(data)/2 data[0]=(data[int(y-1)]+data[int(y)])/2 else: z=(len(data)-1)/2 data[0]=data[int(z)] #replace this for solution return data[0]#These "asserts" using only for self-checking and not necessary for auto-testingif __name__ == '__main__': assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list" assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list" assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average" assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length" print("Start the long test") assert checkio(list(range(1000000))) == 499999.5, "Long." print("The local tests are done.")
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